Haloalkanes And Haloarenes Question 12
Question 12 - 2024 (31 Jan Shift 1)
$CH _3 CH _2 Br+NaOH \xrightarrow{C _2 H_5OH}$ Product $A$
$CH _3 CH _2 Br+NaOH \xrightarrow{H _2 O}$ Product $B$
The total number of hydrogen atoms in product $A$ and product $B$ is
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Answer (10)
Solution
Formula: Elimination Reaction
$CH _3 CH _2 Br+NaOH \xrightarrow{H H _2 O} \xrightarrow{CH _2 OH} CH _2=CH _2$ $CH _3-CH _2-OH$
Total number of hydrogen atom in $A$ and $B$ is 10
