Haloalkanes And Haloarenes Question 12
Question 12 - 2024 (31 Jan Shift 1)
$\mathrm{CH}{3} \mathrm{CH}{2} \mathrm{Br}+\mathrm{NaOH} \xrightarrow{\mathrm{C}_{2} \mathrm{H_5OH}}$ Product $\mathrm{A}$
$\mathrm{CH}{3} \mathrm{CH}{2} \mathrm{Br}+\mathrm{NaOH} \xrightarrow{\mathrm{H}_{2} \mathrm{O}}$ Product $\mathrm{B}$
The total number of hydrogen atoms in product $\mathrm{A}$ and product $B$ is
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Answer (10)
Solution
Formula: Elimination Reaction
$\mathrm{CH}{3} \mathrm{CH}{2} \mathrm{Br}+\mathrm{NaOH} \xrightarrow{\mathrm{H} \mathrm{H}{2} \mathrm{O}} \xrightarrow{\mathrm{CH}{2} \mathrm{OH}} \mathrm{CH}{2}=\mathrm{CH}{2}$ $\mathrm{CH}{3}-\mathrm{CH}{2}-\mathrm{OH}$
Total number of hydrogen atom in $\mathrm{A}$ and $\mathrm{B}$ is 10
