SATHEE: Related Problems with Solution

Related Problems with Solution

Problem 1 : Convex Mirror

Problem Statement: A convex mirror has a focal length of -15 cm. An object is placed at a distance of 30 cm from the mirror. Determine the position and nature of the image formed.

Solution :

Given: Focal length ((f)) = -15 cm, Object distance ((u)) = 30 cm.
Use the mirror equation: $(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}) .$
Substitute the values: $(\frac{1}{- 15} = \frac{1}{v} + \frac{1}{30}) .$
Solve for (v): $(v = 10, cm) .$
Now, use the magnification formula: $(M = - \frac{v}{u}) .$
Substitute the values: $(M = - \frac{10, cm}{30, cm} = - \frac{1}{3}) .$ So, the image is formed at 10 cm from the mirror, on the same side as the object, and it is virtual, upright, and diminished.

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Related Problems with Solution

Problem 1 : Convex Mirror

Solution :

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