SATHEE: Related Problems with Solution

Related Problems with Solution

Problem 1 : A uniformly charged infinite plane has a charge density of $(2, μ {C/m}^{2}) .$ Calculate the electric field at a point 3 meters above the plane.

Solution :

For an infinite uniformly charged plane, the electric field above the plane is constant and perpendicular to the plane.

Electric field (E) due to a uniformly charged infinite plane: $[E = \frac{σ}{2 ϵ_{0}}]$

Where:

σ is the surface charge density $((2 \times 10^{- 6}, {C/m}^{2}))$
ε₀ is the permittivity of free space $((8.85 \times 10^{- 12}, C^{2} / N \cdot m^{2}))$ $

Substitute the values to calculate (E): $[E = \frac{2 \times 10^{- 6}, {C/m}^{2}}{2 \cdot 8.85 \times 10^{- 12}, C^{2} / N \cdot m^{2}} = 112.99, N/C]$

So, the electric field 3 meters above the plane is 112.99 N/C directed upward.

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Related Problems with Solution

Problem 1 : A uniformly charged infinite plane has a charge density of C/m(2,μC/m2). Calculate the electric field at a point 3 meters above the plane.

Solution :

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Problem 1 : A uniformly charged infinite plane has a charge density of $(2, μ {C/m}^{2}) .$ Calculate the electric field at a point 3 meters above the plane.