Related Problems with Solution

Problem 2 : Balance the following redox equation occurring in basic solution:

[MnO4+H2O2MnO2+O2+OH.]

Solution :

To balance this equation in basic solution, follow these steps:

Step 1: Assign oxidation states to each element: [MnO4:Mn7+,O2] [H2O2:H1+,O2] [MnO2:Mn4+,O2] [O2:O0] [OH:O2,H1+]

Step 2: Write down the unbalanced equation: [MnO4+H2O2MnO2+O2+OH.]

Step 3: Break the reaction into half-reactions for oxidation and reduction: [Oxidation:H2O2O2] [Reduction:MnO4MnO2]

Step 4: Balance each half-reaction: Oxidation: [H2O2O2] Add 4 electrons (e⁻) to the left side to balance the charge.

Reduction: [MnO4MnO2] Add 3 electrons (e⁻) to the right side to balance the charge.

Step 5: Multiply the half-reactions by coefficients to balance the number of electrons: [3(H2O2O2)] [4(MnO4MnO2)]

Step 6: Add the balanced half-reactions to get the overall balanced equation: [3H2O2+4MnO43O2+4MnO2+6OH.]