NEET Solved Paper 2019 Question 14
Question: In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2%, 3% and 4% respectively. Then the maximum percentage of error in the measurement X, where $ X=\frac{A^{2}{B^{1/2}}}{{C^{1/2}}D^{3}} $ will be- [NEET 5-5-2019]
Options:
A) -10%
B) 10%
C) $ ( \frac{3}{13} ) $ %
D) 16%
Show Answer
Answer:
Correct Answer: D
Solution:
$ X=\frac{A^{2}{B^{1/2}}}{{C^{1/2}}D^{3}} $
$ \frac{\Delta X}{X}=\frac{2\Delta A}{A}+\frac{1}{2}\frac{\Delta B}{B}+\frac{1}{3}\frac{\Delta C}{C}+\frac{3\Delta D}{D} $
$ =2\times 1+\frac{1}{2}\times 2+\frac{1}{3}\times 3+3\times 4 $
$ =2+1+1+12 $
$ =16 $
