NEET Solved Paper 2019 Question 14

Question: In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2%, 3% and 4% respectively. Then the maximum percentage of error in the measurement X, where $ X=\frac{A^{2}{B^{1/2}}}{{C^{1/2}}D^{3}} $ will be- [NEET 5-5-2019]

Options:

A) -10%

B) 10%

C) $ ( \frac{3}{13} ) $ %

D) 16%

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ X=\frac{A^{2}{B^{1/2}}}{{C^{1/2}}D^{3}} $ $ \frac{\Delta X}{X}=\frac{2\Delta A}{A}+\frac{1}{2}\frac{\Delta B}{B}+\frac{1}{3}\frac{\Delta C}{C}+\frac{3\Delta D}{D} $ $ =2\times 1+\frac{1}{2}\times 2+\frac{1}{3}\times 3+3\times 4 $ $ =2+1+1+12 $ $ =16 $