NEET Solved Paper 2018 Question 35
Question: A block of mass m is placed on a smooth inclined wedge ABC of inclination $ \theta $ as shown in the figure. The wedge is given an acceleration ‘a’ towards the right. The relation between a and $ \theta $ for the block to remain stationary on the wedge is [NEET - 2018]
Options:
A) $ a=g\cos \theta $
B) $ a=\frac{g}{\sin \theta } $
C) $ a=\frac{g}{cosec\theta } $
D) $ a=g\tan \theta $
Show Answer
Answer:
Correct Answer: D
Solution:
In non-inertial frame,
$ \text{N }sin\theta =ma…(i) $
$ \text{N cos }\theta =mg…(ii) $
$ \tan \theta =\frac{a}{g} $ $ a=g\tan \theta $
