NEET Solved Paper 2018 Question 35

Question: A block of mass m is placed on a smooth inclined wedge ABC of inclination $ \theta $ as shown in the figure. The wedge is given an acceleration ‘a’ towards the right. The relation between a and $ \theta $ for the block to remain stationary on the wedge is [NEET - 2018]

Options:

A) $ a=g\cos \theta $

B) $ a=\frac{g}{\sin \theta } $

C) $ a=\frac{g}{cosec\theta } $

D) $ a=g\tan \theta $

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Answer:

Correct Answer: D

Solution:

  • In non-inertial frame, $ \text{N }sin\theta =ma…(i) $ $ \text{N cos }\theta =mg…(ii) $ $ \tan \theta =\frac{a}{g} $ $ a=g\tan \theta $