SATHEE: Work Energy and Power - Result Question 8

Work Energy and Power - Result Question 8

10. A force $F$ acting on an object varies with distance $x$ as shown here. The force is in $N$ and $x$ in $m$ . The work done by the force in moving the object from $x = 0$ to $x = 6 m$ is

[2005]

(a) $18.0 J$

(b) $13.5 J$

(d) $4.5 J$

Show Answer

Answer:

Correct Answer: 10. (b)

Solution:

Work done $=$ area under F- $x$ graph

$=$ area of trapezium $O A B C$

$= \frac{1}{2} (3 + 6) (3) = 13.5 J$

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Work Energy and Power - Result Question 8

10. A force F acting on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from x=0 to x=6m is

Answer:

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10. A force $F$ acting on an object varies with distance $x$ as shown here. The force is in $N$ and $x$ in $m$ . The work done by the force in moving the object from $x = 0$ to $x = 6 m$ is