Work Energy and Power - Result Question 8

10. A force $F$ acting on an object varies with distance $x$ as shown here. The force is in $N$ and $x$ in $m$. The work done by the force in moving the object from $x=0$ to $x=6 m$ is

[2005]

(a) $18.0 J$

(b) $13.5 J$

(c) $9.0 J$

(d) $4.5 J$

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Answer:

Correct Answer: 10. (b)

Solution:

  1. (b)

Work done $=$ area under F- $x$ graph

$=$ area of trapezium $OABC$

$=\frac{1}{2}(3+6)(3)=13.5 J$