SATHEE: Work Energy and Power - Result Question 23

Work Energy and Power - Result Question 23

26. In a simple pendulum of length $l$ the bob is pulled aside from its equilibrium position through an angle $θ$ and then released. The bob passes through the equilibrium position with speed

[2000]

(a) $\sqrt{2 g ℓ (1 + \cos θ)}$

(b) $\sqrt{2 g ℓ \sin θ}$

(d) $\sqrt{2 g ℓ (1 - \cos θ)}$

Show Answer

Answer:

Correct Answer: 26. (d)

Solution:

(d) If1 is length of pendulum and $θ$ be angular amplitude then height

$h = A B - A C = 1 - 1 \cos θ = 1 (1 - \cos θ)$

At extreme position, potential energy is maximum and kinetic energy is zero; At mean (equilibrium) position potential energy is zero and kinetic energy is maximum, so from principle of conservation of energy.

$(K E + P E)$ at $P = (K E + P E)$ at $B$

$0 + m g h = \frac{1}{2} m v^{2} + 0$

$\Rightarrow v = \sqrt{2 g h} = \sqrt{2 g ℓ (1 - \cos θ)}$

Work Energy and Power - Result Question 23

26. In a simple pendulum of length $l$ the bob is pulled aside from its equilibrium position through an angle $θ$ and then released. The bob passes through the equilibrium position with speed

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Work Energy and Power - Result Question 23

26. In a simple pendulum of length l the bob is pulled aside from its equilibrium position through an angle θ and then released. The bob passes through the equilibrium position with speed

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

26. In a simple pendulum of length $l$ the bob is pulled aside from its equilibrium position through an angle $θ$ and then released. The bob passes through the equilibrium position with speed