Waves - Result Question 29
29. The temperature at which the speed of sound becomes double as was at $27^{\circ} C$ is
[1993]
(a) $273^{\circ} C$
(b) $0^{\circ} C$
(c) $927^{\circ} C$
(d) $1027^{\circ} C$
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Answer:
Correct Answer: 29. (c)
Solution:
- (c) We have $c \propto \sqrt{T}$
$\therefore \frac{c_1}{c_2}=\sqrt{\frac{T_1}{T_2}}$
$\Rightarrow \frac{c_1}{2 c_2}=\sqrt{\frac{(27+273) k}{T_2}}$
$\Rightarrow T_2=1200 k=927^{\circ} C$
