Waves - Result Question 29

29. The temperature at which the speed of sound becomes double as was at $27^{\circ} C$ is

[1993]

(a) $273^{\circ} C$

(b) $0^{\circ} C$

(c) $927^{\circ} C$

(d) $1027^{\circ} C$

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Answer:

Correct Answer: 29. (c)

Solution:

  1. (c) We have $c \propto \sqrt{T}$

$\therefore \frac{c_1}{c_2}=\sqrt{\frac{T_1}{T_2}}$

$\Rightarrow \frac{c_1}{2 c_2}=\sqrt{\frac{(27+273) k}{T_2}}$

$\Rightarrow T_2=1200 k=927^{\circ} C$