Wave Optics - Result Question 9
9. In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference
[NEET Odisha 2019]
(a) $11 \frac{\lambda}{2}$
(b) $5 \frac{\lambda}{2}$
(c) $10 \frac{\lambda}{2}$
(d) $9 \frac{\lambda}{2} t$
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Answer:
Correct Answer: 9. (d)
Solution:
- (d) Path difference for destructive interference in YDSE
$ \begin{aligned} & \Rightarrow \Delta X_n=\frac{(2 n-1)}{2} \lambda \quad n=1,2,3 \ldots . . \\ & \Delta X _{5^{\text{th }}}=\frac{9 \lambda}{2} \end{aligned} $
