Wave Optics - Result Question 9

9. In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference

[NEET Odisha 2019]

(a) $11 \frac{\lambda}{2}$

(b) $5 \frac{\lambda}{2}$

(c) $10 \frac{\lambda}{2}$

(d) $9 \frac{\lambda}{2} t$

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Answer:

Correct Answer: 9. (d)

Solution:

  1. (d) Path difference for destructive interference in YDSE

$ \begin{aligned} & \Rightarrow \Delta X_n=\frac{(2 n-1)}{2} \lambda \quad n=1,2,3 \ldots . . \\ & \Delta X _{5^{\text{th }}}=\frac{9 \lambda}{2} \end{aligned} $