System of Particles and Rotational Motion - Result Question 62

65. The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc is

[2006, 2005]

(a) 25MR2

(b) 32MR2

(c) 12MR2

(d) MR2

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Answer:

Correct Answer: 65. (c)

Solution:

  1. (c) M.I. of a uniform circular disc of radius ’ R ’ and mass ’ M ’ about an axis passing though C.M. and normal to the disc is

(d) As we know that,

Rotational energy =12I(ω)2=12(mK2)ω2 And,

Linear kinetic energy =12mω2R2

Required fraction,

=12(mK2)ω212(mK2)ω2+12mω2R2=(K2K2+R2)

69 .

(b) Moment of inertia =r2dm.

Since, ρiron >ρaluminium 

So, whole of aluminium is kept in the core and the iron at the outer rim of the disc.



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