Semiconductor Electronics Materials Devices and Simple Circuits - Result Question 3
3. An LED is constructed from a p-n junction diode using GaAsP. The energy gap is $1.9 eV$. The wavelength of the light emitted will be equal to
[NEET Odisha 2019]
(a) $654 \times 10^{-11} m$
(b) $10.4 \times 10^{-26} m$
(c) $654 nm$
(d) $654 \AA$
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Answer:
Correct Answer: 3. (c)
Solution:
(c) $\lambda=\frac{12400}{E_g} \AA=\frac{12400}{1.9}=6526 \AA \simeq 654 nm$
