Semiconductor Electronics Materials Devices and Simple Circuits - Result Question 3

3. An LED is constructed from a p-n junction diode using GaAsP. The energy gap is $1.9 eV$. The wavelength of the light emitted will be equal to

[NEET Odisha 2019]

(a) $654 \times 10^{-11} m$

(b) $10.4 \times 10^{-26} m$

(c) $654 nm$

(d) $654 \AA$

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Answer:

Correct Answer: 3. (c)

Solution:

(c) $\lambda=\frac{12400}{E_g} \AA=\frac{12400}{1.9}=6526 \AA \simeq 654 nm$