Physical World Units and Measurements - Result Question 3
3. The unit of permittivity of free space, $\varepsilon_o$ is
(a) Coulomb $^{2} /(.$ Newton-metre) ${ }^{2}$
[2004]
(b) Coulomb/Newton-metre
(c) Newton-meter ${ }^{2} /$ Coulomb $^{2}$
(d) Coulomb $^{2} /$ Newton-meter ${ }^{2}$
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Answer:
Correct Answer: 3. (d)
Solution:
- (d) $\varepsilon_o=\frac{q^{2}}{(r^{2}) 4 \pi F}$
$\Rightarrow$ unit of $\varepsilon_o$ is (coulomb) $)^{2} /$ newton-metre ${ }^{2}$
