Physical World Units and Measurements - Result Question 3

3. The unit of permittivity of free space, $\varepsilon_o$ is

(a) Coulomb $^{2} /(.$ Newton-metre) ${ }^{2}$

[2004]

(b) Coulomb/Newton-metre

(c) Newton-meter ${ }^{2} /$ Coulomb $^{2}$

(d) Coulomb $^{2} /$ Newton-meter ${ }^{2}$

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Answer:

Correct Answer: 3. (d)

Solution:

  1. (d) $\varepsilon_o=\frac{q^{2}}{(r^{2}) 4 \pi F}$

$\Rightarrow$ unit of $\varepsilon_o$ is (coulomb) $)^{2} /$ newton-metre ${ }^{2}$