Oscillations - Result Question 56
61. If a simple harmonic oscillator has got a displacement of $0.02 m$ and acceleration equal to $2.0 m / s^{2}$ at any time, the angular frequency of the oscillator is equal to
[1992]
(a) $10 rad / s$
(b) $0.1 rad / s$
(c) $100 rad / s$
(d) $1 rad / s$
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Solution:
- (a) $\omega^{2}=\frac{\text{ acceleration }}{\text{ displacement }}=\frac{2.0}{0.02}$
$\omega^{2}=100$ or $\omega=10 rad / s$
