Oscillations - Result Question 56

61. If a simple harmonic oscillator has got a displacement of $0.02 m$ and acceleration equal to $2.0 m / s^{2}$ at any time, the angular frequency of the oscillator is equal to

[1992]

(a) $10 rad / s$

(b) $0.1 rad / s$

(c) $100 rad / s$

(d) $1 rad / s$

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Solution:

  1. (a) $\omega^{2}=\frac{\text{ acceleration }}{\text{ displacement }}=\frac{2.0}{0.02}$

$\omega^{2}=100$ or $\omega=10 rad / s$