Oscillations - Result Question 21
24. A particle is subjected to two mutually perpendicular simple harmonic motions such that its $x$ and $y$ coordinates are given by
$x=2 \sin \omega t ; \quad y=2 \sin (\omega t+\frac{\pi}{4})$
The path of the particle will be
[1994]
(a) a straight line
(b) a circle
(c) an ellipse
(d) a parabola
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Answer:
Correct Answer: 24. (c)
Solution:
- (c) As phase difference $=\frac{\pi}{4}$, the resultant path of particle is an ellipse.
