Oscillations - Result Question 21

24. A particle is subjected to two mutually perpendicular simple harmonic motions such that its $x$ and $y$ coordinates are given by

$x=2 \sin \omega t ; \quad y=2 \sin (\omega t+\frac{\pi}{4})$

The path of the particle will be

[1994]

(a) a straight line

(b) a circle

(c) an ellipse

(d) a parabola

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Answer:

Correct Answer: 24. (c)

Solution:

  1. (c) As phase difference $=\frac{\pi}{4}$, the resultant path of particle is an ellipse.