SATHEE: Nuclei - Result Question 23

Nuclei - Result Question 23

25. The Binding energy per nucleon of $_{3}^{7} L i$ and $_{2}^{4} H e$ nuclei are $5.60 M e V$ and $7.06 M e V$ , respectively.

In the nuclear reaction $_{3}^{7} L i +_{1}^{1} H \to_{2}^{4} H e + Q$ , the value of energy $Q$ released is :

(a) $19.6 M e V$

(b) $- 2.4 M e V$

(c) $8.4 M e V$

(d) $17.3 M e V$

[2014]

Show Answer

Answer:

Correct Answer: 25. (d)

Solution:

(d) $B E$ of $_{2} H e^{4} = 4 \times 7.06 = 28.24 M e V$

$B E$ of $_{3}^{7} L i = 7 \times 5.60 = 39.20 M e V$

$_{3}^{7} L i +_{1}^{1} H \to_{2} H e^{4} +_{2} H e^{4} + Q$

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