Nuclei - Result Question 23

25. The Binding energy per nucleon of $ _3^{7} Li$ and $ _2^{4} He$ nuclei are $5.60 MeV$ and $7.06 MeV$, respectively.

In the nuclear reaction $ _3^{7} Li+ _1^{1} H \to _2^{4} He+Q$, the value of energy $Q$ released is :

(a) $19.6 MeV$

(b) $-2.4 MeV$

(c) $8.4 MeV$

(d) $17.3 MeV$

[2014]

Show Answer

Answer:

Correct Answer: 25. (d)

Solution:

  1. (d) $BE$ of $ _2 He^{4}=4 \times 7.06=28.24 MeV$

$BE$ of $ _3^{7} Li=7 \times 5.60=39.20 MeV$

$ _3^{7} Li+ _1^{1} H \to _2 He^{4}+ _2 He^{4}+Q$