Motion in a Straight Line - Result Question 45

47. A stone released with zero velocity from the top of a tower, reaches the ground in 4sec. The height of the tower is (g=10m/s2) [1995]

(a) 20m

(b) 40m

(c) 80m

(d) 160m

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Answer:

Correct Answer: 47. (c)

Solution:

  1. (c) Initial velocity (u)=0; Time (t)=4sec and gravitational acceleration (g)=10m/s2.

Height of tower

h=ut+12gt2=(0×4)+12×10×(4)2.=80m.



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