Motion in a Straight Line - Result Question 45

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47. A stone released with zero velocity from the top of a tower, reaches the ground in $4 sec$. The height of the tower is $(g=10 m / s^{2}) \quad$ [1995]

======= ####47. A stone released with zero velocity from the top of a tower, reaches the ground in $4 sec$. The height of the tower is $(g=10 m / s^{2}) \quad$ [1995]

3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed:content/english/neet-pyq-chapterwise/physics/motion-in-a-straight-line/motion-in-a-straight-line—result-question-45.md (a) $20 m$

(b) $40 m$

(c) $80 m$

(d) $160 m$

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Answer:

Correct Answer: 47. (c)

Solution:

  1. (c) Initial velocity $(u)=0$; Time $(t)=4 sec$ and gravitational acceleration $(g)=10 m / s^{2}$.

Height of tower

$h=u t+\frac{1}{2} g t^{2}=(0 \times 4)+\frac{1}{2} \times 10 \times(4)^{2} .=80 m$.