Laws of Motion - Result Question 19
19. Two bodies of mass $4 kg$ and $6 kg$ are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is:
[2020]
(a) $g / 2$
(b) $g / 5$
(c) $g / 10$
(d) $g$
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Answer:
Correct Answer: 19. (b)
Solution:
- (b) Given: Mass $M_1=4 kg$ and $M_2=6 kg$.
Acceleration of the system,
$a=\frac{(m_1-m_2) g}{(m_1+m_2)}$ where $m_1>m_2$
$\therefore a=\frac{(6-4) g}{6+4}=\frac{g}{5}$
Here no option is given according to acceleration of COM of the system.
