Laws of Motion - Result Question 19

19. Two bodies of mass $4 kg$ and $6 kg$ are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is:

[2020]

(a) $g / 2$

(b) $g / 5$

(c) $g / 10$

(d) $g$

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Answer:

Correct Answer: 19. (b)

Solution:

  1. (b) Given: Mass $M_1=4 kg$ and $M_2=6 kg$.

Acceleration of the system,

$a=\frac{(m_1-m_2) g}{(m_1+m_2)}$ where $m_1>m_2$

$\therefore a=\frac{(6-4) g}{6+4}=\frac{g}{5}$

Here no option is given according to acceleration of COM of the system.