Kinetic Theory - Result Question 32
32. If $\gamma$ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is
[2000]
(a) $\frac{25}{2}(\gamma-1)$
(b) $\frac{3 \gamma-1}{2 \gamma-1}$
(c) $\frac{2}{\gamma-1}$
(d) $\frac{9}{2}(\gamma-1)$
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Answer:
Correct Answer: 32. (c)
Solution:
- (c) We know that ratio of specific heats,
$ \gamma=1+\frac{2}{n} \text{ or } n=\frac{2}{\gamma-1} $
[where $n=$ Degree of freedom]
