SATHEE: Kinetic Theory - Result Question 32

Kinetic Theory - Result Question 32

32. If $γ$ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is

[2000]

(a) $\frac{25}{2} (γ - 1)$

(b) $\frac{3 γ - 1}{2 γ - 1}$

(d) $\frac{9}{2} (γ - 1)$

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Answer:

Correct Answer: 32. (c)

Solution:

$γ = 1 + \frac{2}{n} or n = \frac{2}{γ - 1}$

[where $n =$ Degree of freedom]

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Kinetic Theory - Result Question 32

32. If γ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is

Answer:

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32. If $γ$ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is