Kinetic Theory - Result Question 32

32. If $\gamma$ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is

[2000]

(a) $\frac{25}{2}(\gamma-1)$

(b) $\frac{3 \gamma-1}{2 \gamma-1}$

(c) $\frac{2}{\gamma-1}$

(d) $\frac{9}{2}(\gamma-1)$

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Answer:

Correct Answer: 32. (c)

Solution:

  1. (c) We know that ratio of specific heats,

$ \gamma=1+\frac{2}{n} \text{ or } n=\frac{2}{\gamma-1} $

[where $n=$ Degree of freedom]