Gravitation - Result Question 50

53. The escape velocity of a body on the surface of the earth is 11.2km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become

[1997]

(a) 44.8km/s

(b) 22.4km/s

(c) 11.2km/s (remains unchanged)

(d) 5.6km/s

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Answer:

Correct Answer: 53. (b)

Solution:

  1. (b) Escape velcocity

ve=2GMeRe,ve=2GMeRe

veve=MeMe×ReRe

Given Me=2Me and Re=Re2

veve=2MeMe×ReRe/2=4=2

ve=2ve=2×11.2=22.4km/s



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