Electrostatic Potential and Capacitance - Result Question 46
48. The four capacitors, each of $25 \mu F$ are connected as shown in fig. The dc voltmeter reads $200 V$. The charge on each plate of capacitor is
[1994]
(a) $\pm 2 \times 10^{-3} C$
(b) $\pm 5 \times 10^{-3} C$
(c) $\pm 2 \times 10^{-2} C$
(d) $\pm 5 \times 10^{-2} C$
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Answer:
Correct Answer: 48. (b)
Solution:
- (b) Charge on each plate of each capacitor
$ \begin{aligned} Q & = \pm C V= \pm 25 \times 10^{-6} \times 200 \\ & = \pm 5 \times 10^{-3} C \end{aligned} $
