Electrostatic Potential and Capacitance - Result Question 46

48. The four capacitors, each of $25 \mu F$ are connected as shown in fig. The dc voltmeter reads $200 V$. The charge on each plate of capacitor is

[1994]

(a) $\pm 2 \times 10^{-3} C$

(b) $\pm 5 \times 10^{-3} C$

(c) $\pm 2 \times 10^{-2} C$

(d) $\pm 5 \times 10^{-2} C$

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Answer:

Correct Answer: 48. (b)

Solution:

  1. (b) Charge on each plate of each capacitor

$ \begin{aligned} Q & = \pm C V= \pm 25 \times 10^{-6} \times 200 \\ & = \pm 5 \times 10^{-3} C \end{aligned} $