SATHEE: Dual Nature of Radiation and Matter

Dual Nature of Radiation and Matter - Result Question 38

40. A source $S_{1}$ is producing, $10^{15}$ photons per second of wavelength $5000 \AA$ . Another source $S_{2}$ is producing $1.02 \times 10^{15}$ photons per second of wavelength $5100 \AA$ Then, (power of $S_{2}$ ) (power of $S_{1}$ ) is equal to :

[2010]

(a) 1.00

(b) 1.02

(c) 1.04

(d) 0.98

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Answer:

Correct Answer: 40. (a)

Solution:

(a) Energy emitted/sec by $S_{1}, P_{1} = n_{1} \frac{h c}{λ_{1}}$

Energy emitted/sec by $S_{2}, P_{2} = n_{2} \frac{h c}{λ_{2}}$

$∴ \frac{P_{2}}{P_{1}} = \frac{n_{2}}{n_{1}} \cdot \frac{λ_{1}}{λ_{2}}$

$= \frac{1.02 \times 10^{15}}{10^{15}} \cdot \frac{5000}{5100} = 1.0$

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Dual Nature of Radiation and Matter - Result Question 38

40. A source S1 is producing, 1015 photons per second of wavelength 5000\AA. Another source S2 is producing 1.02×1015 photons per second of wavelength 5100\AA Then, (power of S2 ) (power of S1 ) is equal to :

Answer:

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40. A source $S_{1}$ is producing, $10^{15}$ photons per second of wavelength $5000 \AA$ . Another source $S_{2}$ is producing $1.02 \times 10^{15}$ photons per second of wavelength $5100 \AA$ Then, (power of $S_{2}$ ) (power of $S_{1}$ ) is equal to :