SATHEE: Current Electricity - Result Question 89

Current Electricity - Result Question 89

94. A resistance wire connected in the left gap of a metre bridge balances a $10 Ω$ resistance in the right gap at a point which divides the bridge wire in the ratio $3 : 2$ . If the length of the resistance wire is $1.5 m$ , then the length of $1 Ω$ of the resistance wire is :

[2020]

(a) $1.0 \times 10^{- 1} m$

(b) $1.5 \times 10^{- 1} m$

(d) $1.0 \times 10^{- 2} m$

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Answer:

Correct Answer: 94. (a)

Solution:

(a) Let $R_{1}$ be the resistance of resistance wire.

From the balancing condition of metre bridge,

$\frac{R_{1}}{10} = \frac{ℓ_{1}}{ℓ_{2}} = \frac{3}{2} \Rightarrow R_{1} = \frac{30}{2} = 15 Ω$

Length of $15 Ω$ resistance wire is $1.5 m$ .

$∴$ Length of $1 Ω$ resistance wire

$= \frac{1.5}{15} = 0.1 m = 1.0 \times 10^{- 1} m$

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Current Electricity - Result Question 89

94. A resistance wire connected in the left gap of a metre bridge balances a 10Ω resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. If the length of the resistance wire is 1.5m, then the length of 1Ω of the resistance wire is :

Answer:

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94. A resistance wire connected in the left gap of a metre bridge balances a $10 Ω$ resistance in the right gap at a point which divides the bridge wire in the ratio $3 : 2$ . If the length of the resistance wire is $1.5 m$ , then the length of $1 Ω$ of the resistance wire is :