Current Electricity - Result Question 32

34. Two wires of the same metal have same length, but their cross-sections are in the ratio 3:1. They are joined in series. The resistance of thicker wire is 10Ω. The total resistance of the combination will be

[1995]

(a) 10Ω

(b) 20Ω

(c) 40Ω

(d) 100Ω

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Answer:

Correct Answer: 34. (c)

Solution:

  1. (c) Length of each wire =; Area of thick wire (A1)=3A; Area of thin wire (A2)=A and resistance of thick wire (R1)=10Ω. Resistance

(R)=ρA1A (if is constant)

R1R2=A2A1=A3A=13

or, R2=3R1=3×10=30Ω

The equivalent resistance of these two resistors in series

=R1+R2=30+10=40Ω.



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