Atoms - Result Question 44

46. The ground state energy of $H$-atom $13.6 eV$. The energy needed to ionize $H$-atom from its second excited state.

[1991]

(a) $1.51 eV$

(b) $3.4 eV$

(c) $13.6 eV$

(d) $12.1 eV$

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Answer:

Correct Answer: 46. (a)

Solution:

  1. (a) Second excited state corresponds to $n=3$

$ \therefore \quad E=\frac{13.6}{3^{2}} eV=1.51 eV $



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