Atoms - Result Question 44
46. The ground state energy of $H$-atom $13.6 eV$. The energy needed to ionize $H$-atom from its second excited state.
[1991]
(a) $1.51 eV$
(b) $3.4 eV$
(c) $13.6 eV$
(d) $12.1 eV$
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Answer:
Correct Answer: 46. (a)
Solution:
- (a) Second excited state corresponds to $n=3$
$ \therefore \quad E=\frac{13.6}{3^{2}} eV=1.51 eV $
