Atoms - Result Question 43

45. The ionization energy of hydrogen atom is 13.6 eV. Following Bohr’s theory, the energy corresponding to a transition between 3rd and 4th orbit is

[1992]

(a) 3.40eV

(b) 1.51eV

(c) 0.85eV

(d) 0.66eV

Show Answer

Answer:

Correct Answer: 45. (d)

Solution:

  1. (d) E=E4−E3

=−13.642−(−13.632)=−0.85+1.51

=0.66eV

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