Atoms - Result Question 43

45. The ionization energy of hydrogen atom is 13.6 eV. Following Bohr’s theory, the energy corresponding to a transition between 3rd and 4th orbit is

[1992]

(a) $3.40 eV$

(b) $1.51 eV$

(c) $0.85 eV$

(d) $0.66 eV$

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Answer:

Correct Answer: 45. (d)

Solution:

  1. (d) $E=E_4-E_3$

$ =-\frac{13.6}{4^{2}}-(-\frac{13.6}{3^{2}})=-0.85+1.51 $

$ =0.66 eV $