Atoms - Result Question 35
37. Which of the following transitions in a hydrogen atom emits the photon of highest frequency?
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(a) $n=2$ to $n=1$
(b) $n=2$ to $n=6$
(c) $n=6$ to $n=2$
(d) $n=1$ to $n=2$
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Answer:
Correct Answer: 37. (a)
Solution:
(a) $\bar{{}v}=R[\frac{1}{n_1^{2}}-\frac{1}{n_2^{2}}]$ or $\frac{1}{\lambda}=R[\frac{1}{n_1^{2}}-\frac{1}{n_2^{2}}]$
Frequency, $v=R c[\frac{1}{n_1^{2}}-\frac{1}{n_2^{2}}]$
Note: See the greatest energy difference and also see that the transition is from higher to lower energy level. Hence, it is highest in case of $n=2$ to $n=1$.
