Alternating Current - Result Question 30
32. In an experiment, 200 V A.C. is applied at the ends of an LCR circuit. The circuit consists of an inductive reactance $(X_L)=50 \Omega$, capacitive reactance $(X_C)=50 \Omega$ and ohmic resistance $(R)$ $=10 \Omega$. The impedance of the circuit is
[1996]
(a) $10 \Omega$
(b) $20 \Omega$
(c) $30 \Omega$
(d) $40 \Omega$
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Answer:
Correct Answer: 32. (a)
Solution:
- (a) Given: Supply voltage $(V _{a c})=200 V$
Inductive reactance $(X_L)=50 \Omega$
Capacitive reactance $(X_C)=50 \Omega$
Ohmic resistance $(R)=10 \Omega$.
We know that impedance of the LCR circuit (Z)
$=\sqrt{{(X_L-X_C)^{2}+R^{2}}}$
$=\sqrt{{(50-50)^{2}+(10)^{2}}}=10 \Omega$
