SATHEE: Alternating Current - Result Question 30

Alternating Current - Result Question 30

32. In an experiment, 200 V A.C. is applied at the ends of an LCR circuit. The circuit consists of an inductive reactance $(X_{L}) = 50 Ω$ , capacitive reactance $(X_{C}) = 50 Ω$ and ohmic resistance $(R)$ $= 10 Ω$ . The impedance of the circuit is

[1996]

(a) $10 Ω$

(b) $20 Ω$

(d) $40 Ω$

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Answer:

Correct Answer: 32. (a)

Solution:

(a) Given: Supply voltage $(V_{a c}) = 200 V$

Inductive reactance $(X_{L}) = 50 Ω$

Capacitive reactance $(X_{C}) = 50 Ω$

Ohmic resistance $(R) = 10 Ω$ .

We know that impedance of the LCR circuit (Z)

$= \sqrt{(X_{L} - X_{C})^{2} + R^{2}}$

$= \sqrt{(50 - 50)^{2} + (10)^{2}} = 10 Ω$

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Alternating Current - Result Question 30

32. In an experiment, 200 V A.C. is applied at the ends of an LCR circuit. The circuit consists of an inductive reactance (XL)=50Ω, capacitive reactance (XC)=50Ω and ohmic resistance (R) =10Ω. The impedance of the circuit is

Answer:

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32. In an experiment, 200 V A.C. is applied at the ends of an LCR circuit. The circuit consists of an inductive reactance $(X_{L}) = 50 Ω$ , capacitive reactance $(X_{C}) = 50 Ω$ and ohmic resistance $(R)$ $= 10 Ω$ . The impedance of the circuit is