Thermodynamics and Thermochemistry 1 Question 41

44. The reversible expansion ob an ideal gas under adiabatic and isothermal conditions is shown in the figure. Which of the following statement(s) is (are) correct?

(2012)

(a) T1=T2

(b) T3>T1

(c) Wisothermal >Wadiabatic 

(d) ΔUisothermal >ΔUadiabatic 

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Solution:

  1. (a) Since, change of state (p1,V1,T1) to (p2,V2,T2) is isothermal therefore, T1=T2.

(b) Since, change of state (p1,V1,T1) to (p3,V3,T3) is an adiabatic expansion it brings about cooling of gas, therefore, T3<T1.

(c) Work done is the area under the curve of pV diagram. As obvious from the given diagram, magnitude of area under the isothermal curve is greater than the same under adiabatic curve, hence Wisothermal >Wadiabatic 

(d) ΔU=nCvΔT

In isothermal process, ΔU=0 as ΔT=0

In adiabatic process, ΔU=nCv(T3T1)<0 as T3<T1.

ΔUisothermal >ΔUadiabatic 

NOTE Here only magnitudes of work is being considered otherwise both works have negative sign.