Chemical and Ionic Equilibrium 2 Question 36
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36. The of $\mathrm{Ag}{2} \mathrm{CrO}{4} 1.1 \times 10^{-12} 298 \mathrm{~K} \mathrm{mol} / \mathrm{L} \mathrm{Ag}{2} \mathrm{CrO}{4} 0.1 \mathrm{M} \mathrm{AgNO}_{3}$ solution is
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####36. The
3e0f7ab6f6a50373c3f2dbda6ca2533482a77bed (a)
(b)
(c)
(d)
(2013 Adv.)
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Solution:
- PLAN In presence of common ion (in this case
ion) solubility of sparingly soluble salt is decreased.
Let solubility of $\mathrm{Ag}{2} \mathrm{CrO}{4}
$$ \begin{aligned} & \mathrm{AgNO}{3}=x \ & \mathrm{Ag}{2} \mathrm{CrO}{4} \rightleftharpoons 2 \mathrm{Ag}^{+}+\underset{x}{\mathrm{CrO}{4}^{2-}} \ & \mathrm{AgNO}{3} \rightleftharpoons \underset{0.1}{\mathrm{Ag}^{+}}+\underset{0.1}{\mathrm{NO}{3}^{-}} \end{aligned} $$
Total
Thus, $\quad\left[\mathrm{Ag}^{+}\right]^{2}\left[\mathrm{CrO}{4}^{2-}\right]=K{\text {sp }}$