Carboxylic Acids and their Derivatives 1 Question 10
11. When propionic acid is treated with aqueous sodium bicarbonate, $\mathrm{CO}{2}
(a) methyl group
(b) carboxylic acid group
(c) methylene group
(d) bicarbonate group
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Solution:
- $\mathrm{CH}{3}-\mathrm{CH}{2}-\mathrm{COOH}+\mathrm{NaH} \stackrel{}{\mathrm{C}} \mathrm{O}{3} \longrightarrow \mathrm{CH}{3} \mathrm{CH}{2} \mathrm{COONa}
