Carboxylic Acids and their Derivatives 1 Question 10
11. When propionic acid is treated with aqueous sodium bicarbonate, $\mathrm{CO}{2}$ is liberated. The $\mathrm{C}$ of $\mathrm{CO}{2}$ comes from
(a) methyl group
$(1999,2 M)$
(b) carboxylic acid group
(c) methylene group
(d) bicarbonate group
Show Answer
Solution:
- $\mathrm{CH}{3}-\mathrm{CH}{2}-\mathrm{COOH}+\mathrm{NaH} \stackrel{}{\mathrm{C}} \mathrm{O}{3} \longrightarrow \mathrm{CH}{3} \mathrm{CH}{2} \mathrm{COONa}$ $+\mathrm{H}{2} \mathrm{O}+\stackrel{}{\mathrm{C}} \mathrm{O}_{2}$
