Biomolecules Question 36
36. Length of one turn of the helix in a $\beta$-form DNA is approximately
[2000,06]
(a) $3.4 nm$
(b) $2 nm$
(c) $0.34 nm$
(d) $20 nm$
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Answer : a
Hints & Solutions
(a) Length of one turn of the DNA helix is $34 \mathring{A}$.
$1 \mathring{A} = 10^{-1} , \text{nm}$
$\therefore 34 \mathring{A} = 10^{-1} \times 34 = \frac{34 \times 1}{10} = 3.4 , \text{nm}$
